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How many times per second does a tuning fork vibrate if it is producing sound wave in helium gas with frequency of 384Hz?

The speed of sound in helium gas is approximately 965 m/s. The wavelength of the sound wave can be calculated using the formula:

$$\lambda = \frac{v}{f}$$

where:

* $\lambda$ is the wavelength in meters

* $v$ is the speed of sound in meters per second

* $f$ is the frequency in Hertz

Substituting the given values into the formula, we get:

$$\lambda = \frac{965 \text{ m/s}}{384 \text{ Hz}} = 2.51 \text{ m}$$

The distance the wave travel one complete vibration is 2 wavelengths . In this case

$$d= 2 \lambda= 2(2.51\text{ m}) = 5.02\text{ m}$$

Therefore, the tuning fork vibrates 384 times per second, each vibration travels a distance of 5.02 meters in helium gas.

Recording Music

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