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What happens if one bulb burns out on a parallel circuit?

If one bulb burns out in a parallel circuit, the other bulbs will continue to shine. Here's why:

* Independent paths: In a parallel circuit, each bulb has its own separate path for electricity to flow. The current doesn't have to pass through any other bulb to reach its destination.

* Voltage remains constant: All bulbs in a parallel circuit share the same voltage. When one bulb burns out, the voltage doesn't change for the other bulbs.

* Current decreases slightly: The overall current in the circuit will slightly decrease because one path has been removed. However, this usually isn't noticeable.

In contrast, in a series circuit, if one bulb burns out, all the bulbs go out because the circuit is broken.

Here's a simple analogy: Imagine a multi-lane highway where each car represents a bulb. In a parallel circuit, each car has its own lane, so if one car breaks down, the other cars can still drive. In a series circuit, all the cars are in a single lane, so if one car breaks down, it blocks the entire lane.

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