```
v = √(2gh)
```
where:
* v is the velocity of the object in meters per second (m/s)
* g is the acceleration due to gravity (9.8 m/s²)
* h is the height of the object above the ground in meters (m)
In this case, h = 95 feet = 28.95 meters. Plugging this value into the formula, we get:
```
v = √(2 * 9.8 m/s² * 28.95 m) = 19.6 m/s
```
Therefore, a human would be going approximately 19.6 m/s, or 44 miles per hour, if he were to jump off a 95 foot cliff.