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How many different trios could be selected from a chorus of 20 singers?

To calculate this, we can use the combination formula:

$$ C(n, r) = \frac{n!}{r!(n-r)!} $$

where:

- n is the total number of items

- r is the number of items to select

- ! denotes the factorial function (the product of all positive integers up to that number)

In this case, n = 20 and r = 3, so the number of different trios that could be selected is:

$$ C(20, 3) = \frac{20!}{3!17!} $$

$$ = \frac{20 \cdot 19 \cdot 18}{1 \cdot 2 \cdot 3} = 1140 $$

Therefore, there are 1140 different trios that could be selected from a chorus of 20 singers.

Singing

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